Entry

How can I ensure that a window opens above all others.

Mar 22nd, 2006 22:39
Waldi Wolf, Dave Green,

.lift ( aboveThis=None )
   To raise this window to the top of the stacking order in the window
manager, call this method with no arguments. You can also raise it to a
position in the stacking order just above another Toplevel window by
passing that window as an argument.


.lower ( belowThis=None )
   If the argument is omitted, moves the window to the bottom of the
stacking order in the window manager. You can also move the window to a
position just under some other top-level window by passing that Toplevel
widget as an argument.

# e.g.

window.lift()