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Is it possible to call a method in a super class?

Jan 9th, 2003 09:09
Daniel LaLiberte, Martin Honnen,

Although the 'super' keyword is reserved in JavaScript,
there is no super object or comparable feature in JavaScript.  
But at least for a two level 
inheritance hierarchy the methods of the "superclass" constructor are 
acessible as
Although this expression gives you the function, the problem is
that we cannot call as a method by using a normal function call.
JavaScript1.3 introduced apply and call for that so with NN4+ 
you can write:
   // or if you have an array of arguments:
  this.constructor.prototype.methodName.apply(this, arguments);
IE4/5 with JScript5 does not support apply and call (but IE5.5 does) 
so you have to assign the function as a property of the object, 
and then it can be used as a method:
  this.super_methodName =
If that all sounds too abstract consider the following example which 
defines a "class" God and a "subclass" NetGod and calls 
the "superclass"' toString method in the subclass.
function God (name) {
  this.name = name;
God.prototype.toString = function () {
  return 'Name of God: ' + this.name + '\n';
var allah = new God ('Allah');
function NetGod (name, url) {
  this.url = url;
NetGod.prototype = new God();
/* NN4
NetGod.prototype.toString = function () {
  var super_toString = this.constructor.prototype.toString;
  return super_toString.call(this) + 'Home of God: ' + this.url + '\n';
NetGod.prototype.toString = function () {
  this.super_toString = this.constructor.prototype.toString;
  return this.super_toString(this) + 'Home of God: ' + this.url + '\n';
var kibo = new NetGod ('Kibo', 'http://www.kibo.com');